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16x^2+35x+6.5=0
a = 16; b = 35; c = +6.5;
Δ = b2-4ac
Δ = 352-4·16·6.5
Δ = 809
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-\sqrt{809}}{2*16}=\frac{-35-\sqrt{809}}{32} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+\sqrt{809}}{2*16}=\frac{-35+\sqrt{809}}{32} $
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